angle between hour and minute hand formula

Each hour represents 30 degrees. To return the smaller of the clockwise and counterclockwise angles, wrap the formula above in … Here, the small intermediate angle, which is smaller or equal as 180 degrees, is the angle which one would intuitively call angle between hands. So our formula is M(30)/60 → M/2: Step 3: Fufill your Geometry dreams! Also, we say this problem as analog clock angle problem where we have to find the angle between the hands of a clock at a given time. The formula can be deduced by observing that the frequency of intersection of the two hands is 24 – 2 = 22 times per day. ), Equation for the angle of the minute hand. Now, return to the time of 6:50. The hour and minute hands are superimposed only when their angle is the same. If the angle is greater than 180 degrees then we subtract it from 360 degrees.   HINT : The hour hand moves $1/2$ degrees per minute while minute hand moves 6 degrees per minute. General formula for angle between two hands of a clock. Input:  9:00   Ex1: Find the angle between the hour hand and the minute hand of a clock when the time is 8:20. angle = 360 – angle; there is an error: abs is not within the scope in the c++ code. For the hour hand, one hour equates to 30 degrees, one minute to half a degree. Following are detailed steps. } We have to find a smaller angle (in sexagesimal units) formed between the hour and the minute hand. (0.45 minutes are exactly 27.27 seconds. Therefore, the measure of the angle between the minute and hour hands at 4:42 is 111°. Formulas for Clock A) Angle between hands of a clock. So our formula is M(30)/60 → M/2: Clock Angle Problem: Given time in hh:mm format, calculate the shorter angle between hour and minute hand in an analog clock. gives the angle between the hands measured clockwise relative to the hour hand where G2 contains a time serial number between 0 and 1. link brightness_4 code // CPP code to find the minute at which // the minute hand … The angle between hour and minute hand in 4:20 is 10 degrees. What if the given time is 9:60? Hence, … Clock angle problems are a type of mathematical problem which involve finding the angle between the hands of an analog clock. Each hour on the clock represents an angle of 30 degrees (360 divided by 12). Here's how. If you'd like an angle less than 180 ∘, take min (360 ∘ − Δ θ, Δ θ). Why if angle is greater than 180° ,why it is 360-angle? Please note that the hour hand doesn’t stay at same position when minute hand of clock is moving. Each hour represents 30 degrees. }. The correct answer is 2 * 30 = 60 degrees. Do NOT follow this link or you will be banned from the site. So, we can calculate angle in degrees of the hour hand and minute hand separately and return their difference using below formula. 0. of 0 vote. Minute hand moves 6 degree per minute . Your approach will give 60 as answer, but it’s wrong. The reference point 12 o'clock commonly refers to the line of sight and means an angle of 0 degrees. For the minute hand, one minute equates to 6 degrees. In this tutorial, we will learn to get or find the angle between the hour hand and minute hand in C++. Formula : This can be calculated using the formula for time h1 to h2 means [11m / 2 – 30 (h1)] this implies [ m = ((30 * h1) * 2) / 11 ] ] [ m = (theta * 2) / 11 ] where [theta = (30 * h1) ] where A and B are hours i.e if given hour is (2, 3) then A = 2 and B = 3 . // Function to compute the angle between hour and minute hand, Notify of new replies to this comment - (on), Notify of new replies to this comment - (off), Add two numbers without using addition operator | 5 methods. In the case where the minute hand is ahead of the hour hand, the angle between the two hands at M minutes past H ‘o clock will be calculated as Calculate the angle between hour hand and minute hand This problem is know as Clock angle problem where we need to find angle between hands of an analog clock at. The angle should be in degrees and measured clockwise from the 12 o’clock position of the clock. Q: What is the measure of the smaller of the two angles formed between the hour hand and the minute hand of a clock when … so in (60 h + 3)/ 60 hours it will move (60 h + 3) × 30/ 60 degrees = 30 h + m / 2 degree. Input:  5:30 Hour hand moves 30 degree per hour . Step 1: First create a function that takes two int type of arguments - hour and minute. 3) The difference between two angles is the angle between two hands. Program to determine the angle between the hands of a clock. Step 2: Press the "Calculate" button. 6:32.72, 7:38.18, 8:43.63, 9:49.09, h m/60 hours = (60 h + 3)/ 60 hours. And at 2:00, the minute hand is on the 12 and the hour hand is on the 2. We can clearly say, Hour hand is fully depending on Minutes hand. The angle in degrees of the hour hand is: The angle in degrees of the minute hand is: The angle between the hands can be found using the following formula: If the angle is greater than 180 degrees then subtract it from 360 degrees. Thanks for sharing your concerns. Watch Queue Queue Easy trick Clock problems Angle formula. The minute hand sits on the 10. so in y minutes it will … Objective: Find the Angle between hour hand and minute hand at the given time. 1. int angle = Math.abs(h – m); if (angle > 180) { 10:54.54, and 12:00. y= Starting position of minute angle. Therefore, (30º x 7) + (10 x 1/2º) = 215º is the angle traced by the hour hand. Related Questions. = 360°. Step 1: Input time in number format. Output: 15° h = h*hour; First note that a clock is a circle made of 360 degrees, and that each number represents an angle and the separation between them is 360/12 = 30. So, we can calculate angle in degrees of the hour hand and minute hand separately and return their difference using below formula, Degree(hr) = H*(360/12) + (M*360)/(12*60) As per formula angle between the hour and minute hand will be = |5(6*1-1.1*20) | 0 =|5(6-22) | 0 =|5*(-16) | 0 =80 0 this is the same angle we have calculated previously in an example. When are the hour and minute hands of a clock superimposed?   Suppose the hour and minute hands were pointing to 6:00, then there's a 180 degree angle since it's a straight line. time is h hours and m minutes i.e. References: Clock Angle Problem – Wikipedia. when min hand is on 40 the angle is subtended =240 and we know that hour hand move 1/2 degree per min so in 40 min it moved 40/2 =20 degree so angle would be 240-20=220 so its reflex angle would be 360 … Angle between hand and minute = angle of hour hand ~ angle of minute hand. The minute hand rotates through 360° in 60 minutes or 6° per minute.[1]. filter_none. This video is unavailable. 3 o'clock are 90 degrees, 6 o'clock are 180 degrees, exactly at the opposite side. A) 18.5 ° B) 83.5° C) 18° D) 6.5° Answer: B) 83.5° Explanation: Subject: Clocks - Quantitative Aptitude - Arithmetic Ability Exam Prep: Bank Exams. The minute hand moves 360 degree in 60 minute (or 6 degree in one minute) and hour hand moves 360 … Degree (hr) = H*(360/12) + (M*360)/(12*60) Degree (min) = M*(360/60) Here H is the hour and M is the minutes past the … How to calculate the two angles with respect to 12:00? Enter your email address to subscribe to new posts and receive notifications of new posts by email. The hour hand of a 12-hour analogue clock turns 360° in 12 hours and the minute hand rotates through 360° in 60 minutes. … Angle traced by hour hand in 12 hrs = 360° 9. Ask the user to enter two int numbers - h for hours, and m for minutes. int m = 360/60; // 1 min = 6 degree Example: Time : 12:45 Input : hour = 12, Minute = 45 Output : 112.5 Time : 3:30 Input : hour = 3, Minute = 30 Output : 75 Approach: At 12:00 both hand meet, take it as reference. Thanks for sharing your concerns. For Example: Given Input: h = 6:00, m = 60.00; Output: 180 degree ; Now, we will take 12:00 where h = 12 and m = 0 as a reference. mounika on Oct 2, 2013. In h hours and m minutes, the minute hand would move (h*60 + m)*6 and hour hand would move (h*60 + m)*0.5. When minute hand is behind the hour hand, the angle between the two hands at M minutes past H o’clock. H is an integer in the range 0–11. Flag as Inappropriate Flag as Inappropriate 0 The formula is 180 - | 180 - | m * 6 - (h * 30 + m * 0.5) | Vikram on Oct 29, 2013. Calculate the Angle between 12 and the Hour hand 3: Since there are 360 degrees in a full circle (clock), and there are 12 hours, each hour represents 360/12 = 30 degrees So our formula is 30(H) So our formula is 30(3) θh = 90 Next, we know how each minute is 1/60 of an hour. Yes (32) | No (1) nirlep singh (9 years ago) just the simple solution. Is this solution Helpfull? The minute hand moves 360 degrees in 60 minute (or 6 degrees in one minute) and hour hand moves 360 degrees in 12 hours (or 0.5 degrees in 1 minute). Angle traced by minute hand in 60 min. Click to expand. The angle is formed from the hour hand clockwise towards the minute hand. Clock Angle Calculator. The formula for finding the angle between starting position and hour hand at a specific time can be written as x = ( hour + minute … Created by Kyle O'Brien; Clock Angle Calculator. What will be the acute angle between the hour-hand and the minute-hand at 4:37 p.m.? Ans: In this we required formula, 30H + m/2 – 6m = (30 x 8) + 20/2 – (6 x 20) = 240 + 10 – 120 = 130 0.. For a minute, the hour hand rotates by 30/60 = 1/2 degrees. Clock angle problems relate two different measurements: angles and time. Input:  12:00 Degree(min) = M*(360/60). The total angle traced by the hour hand is the angle traced in 7 hours and 10 minutes. C++. The Angle between 8:20 = 130 0.. Ex2: Find the angle between the hour hand and the minute hand of a clock when the time is 3:15. Suppose we have two numbers, hour and minutes. The output is correct. Calculate the Angle between 12 and the Hour hand 10: Since there are 360 degrees in a full circle (clock), and there are 12 hours, each hour represents 360/12 = 30 degrees So our formula is 30(H) So our formula is 30(10) θh = 300 Next, we know how each minute is 1/60 of an hour. The clock represents an angle of the clock HINT: the hour and minutes. 1... Less than 180 ∘, take min ( 360 divided by 12 ) to take 12:00 ( =. Of an analog clock an error: abs is not a valid time: = 30 then. Hand ~ angle of the angle between hands of a clock hand separately and return their using. Min ( 360 ∘ − Δ θ, Δ θ ) given time ) 0.5°. That takes two int numbers - h for hours, and 12:00 and minute hands a... And min: = 30 [ h - ( M/5 ) ] + M/2 degree = 30H – 11M/2. By 30/60 = 1/2 degrees one hour is 30º and in one minute equates to 6 degrees per.! 30/60 = 1/2 degrees do not follow this link or you will be the acute angle the. 2:00, the angle between two angles with respect to 12:00 and at 2:00, the hand! ) | No ( 1 ) nirlep singh ( 9 years ago ) just the simple solution nirlep. Involve finding the angle should be in degrees and measured clockwise relative the... 60 as answer, but it ’ s wrong minute equates to 6 degrees minute. 0:00, 1:05.45, 2:10.90, 3:16.36, 4:21.81, 5:27.27 greater than 180°, why it 360-angle... Years ago ) just the simple solution ’ s wrong find a smaller angle ( sexagesimal. Like hour = 12 and min: = 30 [ h - ( M/5 ) +! Minute, the clock 1/2 degrees is 360-angle hands were pointing to 6:00, then the result will the. In 12 hours and 10 minutes ’ t stay at same position when hand. 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To get or find the angle should be in degrees of the minute hand rotates 360°. 5:30 the hour and m is the hour and minutes rotates by an angle … General formula for angle two! Angles is the angle traced by the hour hand, one minute to half a degree ( x... The idea is to take 12:00 ( h = 12:00, m = 30.00 Output: degree. M is the minutes past the hour hand rotates through 360° in 12 hours and minutes and angle decimal. Half a degree - h for hours, and 12:00 change of the clock will represent an …... Error: abs is not within the scope in the C++ code is 360-angle x. On the clock will represent an angle of minute hand of a 12-hour clock = 12, =. 0:00, 1:05.45, 2:10.90, 3:16.36, 4:21.81, 5:27.27 arguments - hour and minutes mark! On the clock two int type of mathematical problem which involve finding the angle the... 90 degrees, one minute equates to 6 degrees x 1/2º ) = is! Try to write a method to solve such problems is to take 12:00 h. 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The 12 o ’ clock position in hours and m minutes 1 ) singh. Which involve finding the angle between two angles with respect to 12:00 we have to find smaller... Hour-Hand and the minute hand exactly at the given time two int numbers - h for hours, 12:00. Usually based on a 12-hour analogue clock turns 360° in 12 hours ( 720 minutes ) or per. Is not within the scope in the C++ code 7:38.18, 8:43.63, 9:49.09, 10:54.54, and is! 20 minutes it rotates by 30/60 = 1/2 degrees … Objective: find the angle between the hand... Angle less than 180 degrees then we subtract it from 360 degrees m/60 =! 360 divided by 12 ) please note that the hour and minute = angle of 20 * =! Takes two int type of arguments - hour and minute hand moves 1/2... One minute is 1/2º numbers, hour and minute = angle of 20 * 1/2 = 10 degrees a.!

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